Write separate equations for oxidation and reduction. Reduction: + 1 H + e − → 0 H ( i n H 2) Oxidation: 0 A l → + 3 A l + 3 e −. Multiply the reduction equation by 3 to obtain an equation with the same number of electrons as the oxidation equation: Reduction: 3 H + + 3 e − 3 H 0 ( i n H 2) Oxidation:
Cr(H 2O)3 + 6 − ⇀ ↽ − Cr(H 2O) 5(OH)2 + + H + (aq) However, if you write it like this, remember that the hydrogen ion isn't just falling off the complex ion. It is being pulled off by a water molecule in the solution. Whenever you write "H +(aq) " what you really mean is a hydroxonium ion, H 3 O +.b. Fe 2 O 3 + 3 CO 2 Fe + 3 CO 2 in acidic solution c. 5 CO + I 2 O 5 5 CO 2 + I 2 in basic solution ; Write balanced equations for the following reactions: a. Cr(OH) 3 + Br 2 CrO 4 2-+ Br-in basic solution 10 OH-+ 2 Cr(OH) 3 + 3 Br 2 2 CrO 4 2-+ 8 H 2 O + 6 Br-b. O 2 + Sb H 2 O 2 + SbO 2-in basic solution 2 OH-+ 2 Sb + 3 O 2 + 2 H 2 O 2 SbO 2
Coordination Number 5. Square pyramid Geometry: Oxovanadium salts (Vanadyl, VO 2+) often show square pyramidal geometry, for example, VO (acac) 2. Note that the Vanadium (IV) can be considered coordinatively unsaturated and addition of pyridine leads to the formation of an octahedral complex. Trigonal Bipyramid Geometry: The structure of [Cr